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Aratati ca (2X+1)²-5X²+(X-2)(X+2)-4X=-3 pentru orice x numar real.

Dau coronita +50 puncte !!!


Răspuns :

(2x+1)²-5x²+(x-2)(x+2)-4x=3
Rezolvam pe rand
(2x)²+2*2x*1+1²=4x²+4x+1
(x-2)(x+2)=x²-4
Revenim la exercitiu
4x²+4x+1-5x²+x²-4-4x=3
4x²+x²-5x²=0(reducem)
4x-4x=0(reducem)
1-4=-3 si am aratat ca e egal cu -3


(2x+1)²-5x²+(x-2)(x+2)-4x=
4x²+4x+1-5x²+x²-4-4x=
5x²-5x²+4x-4x+1-4=
1-4=-3
succes