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rezolvati in multimea nr nat 3{12+3*[40-2*(28-3*5)]}-5x=7

Răspuns :

3{12+3*[40-2*(28-3*5)]}-5x=7
3[12+3*(40-2*13)]-5x=7
3[12+3*14]-5x=7
3*54-5x=7
162-5x=7
-5x=-155
5x=155
x=31