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c=x ∈ nr. naturale / (1+2·2²·2⁴⁹ ) : ( 1+ 2⁵² ) ≥ x

Răspuns :

C={x∈N/ (1+2*2²*2⁴⁹):(1+2⁵²)≥x}
(1+2*2²*2⁴⁹):(1+2⁵²)≥x
(1+2⁵²):(1+2⁵²)≥x
1≥x
x∈{0,1}⇒ C={0,1}