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sa se determine numarul natural x astfel incat fractia 4+x supra 6+x sa fie egala cu:
a)9/11 b)4/6 c)7/9 d)103/105 (toate sunt supra adica 9 supra 11)

dau coronita!


Răspuns :

a)11(4+x)=9(6+x)
44+11x=54+9x
11x-9x=54-44
2x=10
x=5
b)6(4+x)=4(6+x)
24+6x=24+4x
6x-4x=24-24
2x=0
x=0
c)9(4+x)=7(6+x)
36+9x=42+7x
9x-7x=42-36
2x=6
x=3
d)105(4+x)=103(6+x)
420+105x=618+103x
105x-103x=618-420
2x=198
x=99