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suma a patru numere consecutive este 50. afla numerele

Răspuns :

a+a+1+a+2+a+3=50
4a+6=50
4a=50-6
4a=44
a=44:4
a=11
a+1=11+1=12
a+2=11+2=13
a+3=11+3=14
V:11+12+13+14=23+27=50
sper ca te.am ajuta <3
a+a+1+a+2+a+3=50
4a+6=50
4a=50-6
4a=44
a=44:4=11
b=12
c=13
d=14

11+12+13+14=50