E
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D /_________________/C
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A_/______________________________________________________/B
AB=4xm
BC=3xm
CD=1xm
DA=2xm
AB+BC+CD+DA=60 cm
4m+3m+m+2m=60
10m=60
m=6
AB=24cm
BC=18cm
CD=6cm
DA=12cm
Pt. partea a doua folosim teorema lui Thales:
DCllAB, rezulta: DE/AE=CD/AB=CE/BE
(AE-AD)/AE=CD/AB=(BE-BC)/BE
Notam: x=AE si y=BE
(x-12)/x=6/24=(y-18)/y
(x-12)/x=6/24=1/4
4(x-12)=x
3x=48
x=16cm
6/24=(y-18)/y=1/4
4(y-18)=y
3y=72
y=24cm