a)
CnH2n+2
CnH2n
amestec echimolar, putem considera cate un mol din fiecare
12n+2n+2=14n+2
12n+2n=14n
(28n+2) g......(.4n+2) g H
100 g ................15,15 ==>n=7
C7H16 alcanul A
C7H14 alchena cu izomerii
C-C(CH3)2-C-C=C 4,4-dimetil -1-pentena D
C-C(CH3)2-C=C-C 4,4-dimetil 2-pentena [ cis, trans] B si C
B,C,D (alchenele izomere)
+H2-------->C-C(CH3)2-C-C-C
alcanul A 2,2-dimetil-pentan
b) B si C izomeri geometrici
(B,C) si D izomeri de pozitie
c)
D prin halogenare in pozitia alilica
C-C(CH3)2-C-C=C
+Cl2 ------->C-C(CH3)2-C(Cl)-C=C
+Hcl
98 g 132,5
g
9,8
g.......................................x=13,25 g (mt)
η/100= mp/mt ==> mp = 13,25*9/10
= 11,925 (g)
