afli mai intii lungimea ipotenuzei cu ajutorul teoremei lui Pitagora
[tex] BC^{2}= 6^{2} + 8 ^{2} \\ BC=10 \\ sinB= \frac{x}{y} = \frac{AC}{BC} = \frac{4}{5} \\ sinC= \frac{AB}{BC}= \frac{3}{5} \\ cosC= \frac{AC}{BC}= \frac{4}{5} \\ tgB= \frac{AC}{AB} = \frac{4}{3} \\ \\ tgC= \frac{AB}{AC}= \frac{3}{4} [/tex]
