a)m:n=p =>m=pxn
m+n+p=107
m+n=81 =>81+p=107
p=107-81
p=26
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m+p=104 =>m+26=104
m=104-26
m=78
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m=pxn
78=26xn
n=78:26
n=3
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verificare
78:3=26
78=26x3
78=78
b)a:b=c +r =>a=cxb+r
a+b+c+r=91
b+c+r=28 =>a+28=91 a=91-28 a=63
a+r=74 =>63+r=74 r=74-63 r=11
b si r sunt nr consecutive impare
restul este mai mic decat impartitorul deci b va fi urmatorul numar impar ,adica 13
avem a=63 b=13 r=11
a+b+c+r=91
63+13+11+c=91
c=91-87
c=4
verfificare
63:13=4 rest 11
63=4x13+11
63=52+11
63=63