pV = v RT ( v= niu) !!!!!
pV= m/MRT
pM= ρ RT
R=0,082 L. atm/K .mol ; T=273-10=263 K ; p= 81060 Pa = 81060/101250 atm
M= ρ RT/p= 42 g/ mol
masa moleculara medie M= M1v1/(v1+v2) +M2v2/(v1+v2) v1=v2=1mol [v=niu]
hidrocarbura A are NE=0 => CnH2n+2
B are NE=2 ==> CnH2n-2
masa moleculara medie M=(12n+2n+2)/2 + (12n+2n-2)/2 = 42 ==> n=3
A = C3H8
B = C3H4