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2√3-1supra√3-2-√3supra √12-1-√3supra√3

Răspuns :

(2√3-1) supra √3-(2-√3) supra √12 -(1-√3)supra √3 =
se rationalizeaza numitorii
√3(2√3-1)/3  -√3(2-√3)/2.3-√3(1-√3)/3=
(2.3-√3)/3-(2√3-3)/6-(√3-3)/3=
aducem la acelasi numitor
(12-2√3-2√3+3-2√3+6)/6=(21-6√3)/6=3(7-2√3)/6=(7-2√3)/2