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simplificati fractia 2x^2-18\3x+9

Răspuns :

[tex] \frac{2 x^{2}-18 }{3x+9} = \frac{2( x^{2} -9)}{3(x+3)} = \frac{2(x+3)(x-3)}{3(x+3)} = \frac{2(x-3)}{3} [/tex]