1)
x/4=1, x=4
(x+1)/7=1, x+1=7, x=6
(x-2)/10=1, x-2=10, x=12
14/(x+2)=1, x+2=14, x=12
23/(x-1)=1, x-1=23, x=24
104/(20x+4)=1, 20x+4=104, 20x=100, x=5
2)
(n+2)/15<1
n+2<15
n<13, dar n=N, rezulta A={0,1,2,3,4,5,6,7,8,9,10,11,12}
(n+1)/7>1 (nu se vede in enunt, am ales eu supraunitara)
n+1>7
n>6, dar n=N, rezulta B={7,8,9,10,11,12,13,14,15,..., +infinit}
A intersectat cu B={7,8,9,10,11,12}
3 si 4 au enunturi incomplete ca si 2 (dar la 2 mai poti presupune).