ma = (a+b)/2 = 4 intregi si 5/12 = (4×12 + 5)/12 = (48+5)/12 = 53/12
rezulta a + b = 2 × 53/12 = 53/6
a) a = 5 intregi 1/3 = (5×3+1)/3 = 16/3
16/3 + b = 53/6
b = 53/6 - 16/3 = (53 - 48)/6 = 5/6
b) a = 3 intregi si 3/4 = (3×4+3)/4 =15/4
15/4 + b = 53/6
b = 53/6 - 15/4 = (106 - 45)/12 = 61/12
c) 2 intregi 7/9 - (2×9+7)/9 = 25/9
25/9 + b = 53/6
b = 53/6 - 25/9 = (159 - 50)/18 = 109/19