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Un motor termic dezvolta o putere de 50 kW. Randamentul lui este de 30%. Cati litri de benzina a consumat el daca a functionat 10 ore?

Răspuns :

η=[tex] \frac{L}{Q} [/tex]
P=50 kW=50000 W
t=10 h=36000 s
P=[tex] \frac{L}{t} [/tex] =>L=P*t=1800000000 J =1,8 GJ
η=[tex] \frac{L}{Q} \ \textless \ =\ \textgreater \ 0,30= \frac{1800000000}{Q} =\ \textgreater \ Q= \frac{1800000000}{0,30} =6000000000 J [/tex]=6000 MJ=6 GJ
q=[tex] \frac{Q}{m} [/tex]
q=45,98 MJ
q=[tex] \frac{Q}{m} \ \textless \ =\ \textgreater \ 45,98= \frac{6000}{m} =\ \textgreater \ m= \frac{6000}{45.98}=130, 491 l [/tex]