Aplicam formula: [tex]t^2-St+P = 0[/tex] si rezolvam ecuatia, x si y fiind cele 2 radacini:
S = 5
P = 6
=>
[tex] t^{2} -5t+6=0 \\ \Delta = 25-24 = 1 \\ \\ t_{1,2} = \frac{5\pm 1}{2} \Rightarrow \left \{ {{t_1 = 3} \atop {t_2 = 2}} \right. \\ \\ =\ \textgreater \ x = 3, y = 2 \\ \\ x-y = 3-2 \Rightarrow x-y = 1[/tex]
