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Imi rezolvati si mie trei ex prin metoda racului ( metoda mersului invers) VĂ ROG!!!!!!! 1 . 6+[15-(8:a×7+7)]×5=8:(1×4)+3×3. 2. 4+4×[4+4×(4+h:4)+4]:4=52. 3. 234+[(88:4+j)-78:6]×23=809

Răspuns :

6+[15-(8:a×7+7)]×5=8:4+9
6+[15-(8:a×7+7)]×5=11
6+[15-(8:a×7+7)]=11×5
6+[15-(8:a×7+7)]=55
[15-(8:a×7+7)]=55-6
[15-(8:a×7+7)]=49
(8:a×7+7)=49+15
(8:a×7+7)=64
8:a×7=64-7
8:a×7=57
8:a=57×7
8:a= 399
8: a = 399
a= 399:8
a=44;