CxH(2x+2)O ⇒ CxH2x + H2O
alcool : %C = 12x/M
alchena : %C = 12x/(M-18)
12x·100/(14x+18) = 600x/(7x+9)
12x·100/14x = 600/7 = 85,714
600x/(7x+9) = 64,87
7x +9 = 9,25x 2,25x = 9 x = 4 C4H10OH
izomeri : 1butanol ; 2butano (2 enantiomeri)l; 2metilpropanol ; tertbutanol