a+b+c=235
a=primul muncitor,b=al doilea muncitor,c=al treilea muncitor;
{a,b,c}i.p.{0,5;0,(6);0,4}
a pe0,5=k =>a=k*10/5=2k;
b pe0,(6) => b=k*9/6=3k/2;
c pe 0,4=k => c=k*10/4=5k/2;
2k+3k/2+5k/2=235;(aduci la acelasi numitor adica2 prin aplificarea fractilor)
4k+3k+5k=470
12k=470
k=39,16
a=3916/100*2=78,32
b=3916/100*3/2=58,74
c=3916/100*5/2=97,9
78,32+58,74+97,9=234,96care prin aproximare da 235