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×la 2 +17 ×-60 ....intrebarea numaru 2 ...xla 2 -11x+24 .....intrebarea numaru 3 ..xla 2 -12x+35.va rog frumos ajutati-ma

Răspuns :

x²+17x-60=
Δ=289-4·(-60)
Δ=289+240
Δ=529 =>√Δ=23
x₁=(-17-23)/2=(-20)
x₂=(-17+23)/2=3 =>ecuatia se descompune asa : (x+20)(x-3)

x²-11x+24=
Δ=(-11)²-4·24
Δ=121-96
Δ=25 =>√Δ=5
x₁=(11-5)/2=3
x₂=(11+5)/2=8 =>ecuatia se descompune asa : (x-8)(x-3)

x²-12x+35=
Δ=(-12)²-4·35
Δ=144-140
Δ=4 =>√Δ=2
x₁=(12+2)/2=7
x₂=(12-2)/2=5 =>ecuatia se descompune asa : (x-5)(x-7)