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radical din X+1-radical X+6 =5

Răspuns :

(√x+1-√x+6)²=5²
x+1-2√(x+1)(x+6)-x-6=25
-2√(x+1)(x+6)=30
(-√(x+1)(x+6)²=15²
(x+1((x+6)=225
x²+7x+6=225
x²+7x+6-225=0
x²+7x-219=0
Δ=925
√Δ=5√37
x₁=(-7+5√37)/2
x₂=(-7-5√37)/2

eu am rezolvata cand sub radical este x+1  si x+6