| |x+6| -7|=2
1. |x+6|-7=2
|x+6|=9 a. x+6=9; x=3, 3∈S
b. x+6=-9; x=-15, -15∈S
2. |x+6|-7=-2
|x+6|=5 a. x+6=5, x=-1, -1∈S
b x+6=-5, x=-11, -11∈S
verificam fiecare solutie
solutia x=3 ||3+6|-7|=2
x=-15 | |-15+6|-7|=|9-7|=2
x=-11 | |-11+6|-7|=|5-7|=2
x=-1 | |-1+6|-7|=|5-7|=2
S={-15; -11; -1; 3}