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(4a-3)(4a+3) va rog ajutatima

Răspuns :

(4a-3)(4a+3) =
(4a)² - 3² =
16a²-9 ( raspunsul )
(4a-3)(4a+3) = (4a)²-3²= 16a²-9 ⇒ 16a² = 9 ⇒ a² = [tex] \frac{9}{16} [/tex] ⇒ a = [tex] \frac{ \sqrt{9} }{ \sqrt{16} } [/tex] ⇒ a = [tex] \frac{3}{4} [/tex]