din [tex] \frac{BD}{BC}= \frac{25}{169} [/tex]
rezulta ca BD=25x si BC=169x
[tex]DC=BC-BD=144x \\ AC^2=BC*DC=169x*144x \\ AC=156x \\ AD^2=BD*DC \\ AD^2=AB^2-BD^2 \\ 25x*144x=4225-625 x^{2} \\ 4225 x^{2} =4225 \\ x=1 \\ AC=156*1=156cm \\ BC= \sqrt{AB^2+AC^2} = \sqrt{65^2+156^2}=169cm [/tex]