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Cat face integrala din x^2 supra 1+x^6 dx?

Răspuns :

Salut,

[tex]\Big\int\dfrac{x^2dx}{1+x^6}=\dfrac{1}3\cdot\int\dfrac{3x^2dx}{1+(x^3)^2}=\dfrac{1}3\cdot\int\dfrac{(x^3)^{'}dx}{1+(x^3)^2}=\dfrac{arctgx^3}3+C[/tex]

Green eyes.