a= primul numar
b = al 2-lea numar
c = al 3-lea numar
a + b + c = 100
a = b : 3 => b = 3×a
a = c : 6 => c = 6×a
a |__|
b |__|__|__|
c |__|__|__|__|__|__|
avem 10 segmente egale = 100
100:10 = 10 ( un segment)
a = 10
b = 3×10 = 30
c = 6×10 = 60
Verificare:
10 + 30 + 60 = 100
a = 10
b = 30
c = 60