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Daca a b c sunt nr naturale astfel incat a+b=8 b+c=3 c+d=10 stabiliti daca nr n=7a+15b+10c+2d este patrat perfect

Răspuns :

n=7a+15b+10c+2d=7a+7b+8b+8c+2c+2d=7(a+b)+8(b+c)+2(c+d)=7*8+8*3+2*10=56+24+20=100=[tex] 10^{2} [/tex]