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ovidiu,marian si alexandra au impreuna 100 de nuci daca fiecare mananca acelas nr de nuci lui ovidiu ii raman 39 de nuci lui marian ii raman 25 de nuci si alexandrei ii raman 21 de nuci .Cate nuci a avut fiecare? rezolva prin metoda grafica cu suma si diferenta

Răspuns :

O /_____/.........................+39............./
M /_____/..................+25.........../
A /_____/................+21......./

100 - (39+25+21)=100-85=15

1+1+1=3 (segmente egale)

15:3=5 (valoarea unui segment)

Ovidiu=1×5+39=5+39=44 (nuci)

Marian=1×5+25=5+25=30 (nuci)

Alexandra=1×5+21=5+21=26 (nuci)