c+m=42 lei
c+f=54 lei
f+m=40 lei
c,m,f=? ; c+m+f=?
c+m+c+f+f+m=42+54+40
2c+2m+2f=136
2(c+m+f)=136
c+m+f=136:2
c+m+f=68
42+f=68
f=68-42 => f=26
c+26=54
c=54-26 => c=28
26+m=40
m=40-26 => m=14
Solutia: c+m+f=28+14+26=68 lei
o pereche de manusi=14 lei
o caciula= 28 lei
un fular= 26 lei