a= primul numar
b = al 2-lea numar
c = al 3-lea numer
a+b+c = 96
a = 2×c
b = a:4-2
a |_____|_____|_____|_____|
b |_____|-2
c |_____|_____|
avem 7 segmente egale -2 = 96
96+2 = 98
98:7 = 14( un segment)
a = 4×14 = 56
b = 14 - 2 = 12
c = 2×14 = 28
VERIFICARE:
56+12+28 = 96
a = 56
b = 12
c = 28