Notam cu a,b,c numerele
a+b+c = 3 333
b = 3×a:2 |×2
2×b = 3×a
c = 2×b
a |____|____|
b |____|____|____|
c |____|____|____|____|____|____|
avem 11 segmente egale =3 333
3 333 : 11 = 303 (un segment)
a = 2×303 = 606
b = 3×303= 909
c = 6×303 = 1 818
Verificare:
606+909+1 818 = 3 333
a = 606
b = 909
c = 1 818
