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daca 4a-5b supra 3a+3b=0,8(3) aflati cat la suta din a reprezinta b?
Multumesc! Si dau coroana


Răspuns :

[tex] \frac{4a-5b}{3a+3b}=0.8(3)[/tex]

atunci 
[tex] \frac{4a-5b}{3a+3b} = \frac{83-8}{90} [/tex][tex] =\frac{75}{90} (poti simplifica cu 15) = \frac{5}{6} [/tex]
=>[tex] \frac{4a-5b}{3a+3b}= \frac{5}{6} [/tex]
=>(4a-5b)*6=(3a+3b)*5=
=24a-30b=15a+15b=
=24a-15a=15b+30b=>
=>9a=45b=>a=5b=>b=[tex] \frac{1}{5} [/tex]*a(amplifici cu 20)
=>b=[tex] \frac{20}{100}*a [/tex]=> b=20%*a
Sper ca te-am ajutat !