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Afla valoarea lui a început fiecare caz: 10×10+4×(5×5-a)-81÷9×4=92. 100+2×3×(41-a)-64÷8×3×3=7×10

Răspuns :

Bună!

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[tex]10*10+4*(5 *5- a)-8 1:9 *4 =92 < = >[/tex]

[tex]<=> 100+4*(25-a)-9*4=92 <=>[/tex]

[tex]<=> 100+100-4a-36=92 < =>[/tex]

[tex]<=> 164-4a= 92 < = >[/tex]

[tex]<=> -4a=-72 => {\boxed {\mathbf{a=18}}[/tex]

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[tex]100+2*3*(4 1-a)- 64:8*3*3 =7*1 0 <=>[/tex]

[tex]<=> 100+6*(41-a)-8*9=70 <=>[/tex]

[tex]<=> 100+246-6a-7 2=70 <=>[/tex]

[tex]<=> 274-6a=70 <=>[/tex]

[tex]<=> -6a=-2 04 => {\boxed{\mathbf{a=34}}[/tex]