Notam cu a,b,c cele 3 numere
a+b+c = 506
b+27 =a
b-28 = c
a |_____|+27
b |_____|
c |_____|-28
avem 3 segmente egale +27 -28 = 506
506-27+28 = 507
507:3 = 169 ( un segment)
a = 169+27 = 196
b = 169
c = 169 -28 = 141
Verificare:
196+169+141 = 506
Raspuns:
a = 196
b = 169
c = 141