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Fie x un nr real ,astfel incat x la puterea 16=2 .calculati (x+1)(x-1(x la puterea a2a+1)(x la puterea a4a+1)(x la puterea a8a+1) repede pls

Răspuns :

(x+1)(x-1)(x^2+1)(x^4+1)(x^8+1)=
=(x^2-1)(x^2+1)(x^4+1)(x^8+1)=
=(x^4-1)(x^4+1)(x^8+1)=
=(x^8-1)(x^8+1)=
=x^16 -1=2-1=1