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Se amesteca 200 g solutie CuCl2 10% cu 20 moli de apa si cu 0,2 moli CuCl2.Concentratia procentuala a solutiei nou formate este?

Răspuns :

ms1=200 g
C1=10
nH2O=20 moli
nCuCl23=0,2 mlo
Cf=?
md1=C*ms1/100=10*200/100=20 g
mH2O1=ms-md=200g-20g =180 g
MH2O=2*1+16=18
mH2O=n*M=20*18=360g
MCuCl2=64+71=135
m=n*M=0,2*135=27 g
mdf=20 g+27=47 g
msf=180+360+47=587
C=mdf/msf*100=47/587*100=8%