1)
1-b
2-a
3-d
4-e
5-c
2)
a) B- o-clorotoluen
C- p-clorotoluen
b) 1- substitutie la catena laterala
2- substitutie pe nucleul benzenic
c) m A = 506 kg
toluen + Cl2 => A + HCl
r=90%
92 kg/kmol toluen .... 126.5 kg/kmol A
x kg toluen .........506 kg A
x= 506 * 92 / 126.5 = 368 kg toluen (mp)
r = mp/mt x 100 => mt = mp x 100/ r => mt = 368 *100/90 = 408.88 kg toluen
mt= masa tepretica
mp=masa practica
r= randament.
d= m/V
V toluen necesar = m toluen/d => V toluen = 408.88 kg / 870 kg/m^3 = 0.469 m^3 toluen.
d= densitatea
m= masa
V= volumul.
