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Dacă x,y€R si x la puterea 2 + y la puterea 2 - 6x - 10y+30=0. Sa se arate ca 4

Răspuns :

[tex]x^2+y^2-6x-10y+30=0\\ x^2-6x+9+y^2-10y+25-4=0\\ (x-3)^2+(y-5)^2=4\\ i) \left \{ {{x-3=0} \atop {y-5=2}} \right. \Leftrightarrow \left \{ {{x=3} \atop {y=7}} \right.\\ ii) \left \{ {{x-3=2} \atop {y-5=0}} \right. \Leftrightarrow \left \{ {{x=5} \atop {y=5}} \right. \\ S:(x,y)\in \{(3,7);(5,5)\}[/tex]