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Help me x^2+4x+3 si 1/x+1 - 1/x+3

Răspuns :

iau separat x^2 +4x+3
x^2 + 4x + 3= x^2 + x + 3x +3= x( x +1) + 3(x + 1)= (x +1)(x+3)

1/(x+1) - 1/(x+3) =
(x +3 -x-1 )/ (x+1)(x+3)=
2/ (x+1)(x+3)