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Aflati trei numere naturale consecutive care au media aritmetica 35

Răspuns :

(a+b+c):3=35
a+b+c= 75
24 25 26
[a+(a+1)+(a+2)] :3=35
[a+(a+1)+(a+2)] =35x3
a+(a+1)+(a+2) =105
3a+3=105
3a=105-3
3a=102
a=102:3
a=34

a+1=34+1=35
a+2=34+2=36

Nr.sunt: 34,35,36

Verificare (34+35+36):3=35