a;b;c;d.........x nr.
x-a=11
a+b+c=(x-a)*6......=> a+b+c=11*6....=> a+b+c=66
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sa se afle numerele
a=66:3-1
a=22-1
a=21
x=66:2-1
x=33-1
x=32
=> numerele sunt: 21; 22; 23; 24; 25; 26; 27; 28; 29; 30; 31 si 32
32-21=11
21+22+23=66
66:6=11
=> 66 > 11 de 6 ori