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Afla media geometrica si media armonica pentru numerele [tex]28 \sqrt{3} si 12 \sqrt{3} [/tex] .

Răspuns :

[tex]M.g.= \sqrt{28 \sqrt{3}*12 \sqrt{3} } = \sqrt{28*12*3} = \sqrt{2 ^{2}*7*2 ^{2} *3*3 } =12 \sqrt{7} [/tex]
[tex]M.a.= \frac{28 \sqrt{3} +12 \sqrt{3} }{2} = 20 \sqrt{3} [/tex]
[tex]M.h.= \frac{M.g.}{M.a.} = \frac{12 \sqrt{7} }{20 \sqrt{3} } = \frac{3 \sqrt{7} }{5 \sqrt{3} } = \frac{3 \sqrt{21} }{15} = \frac{ \sqrt{21} }{5} [/tex]