notam:
a = prima zi
b = a 2-a zi
c = a 3-a zi
a+b+c = 61
c = 2×a+18
c = b+25 => b = c-25
a |___|
b |___|___| +18 -25
c |___|___|+18
Avem 5 segmente egale +18+18-25 = 61
61-18-18+25 = 25+25 = 50
Aflam cate tone rosii s-au cules in prima zi
50 : 5 = 10 ( tone)
Aflam cate tone rosii s-au cules a 2-a zi
10×2+18-25 = 20+18-25 = 13 (tone)
Aflam cate tone rosii s-au cules a 3-a zi
10×2+18 = 20+18 = 38 ( tone)
Verificare:
10+13+38 = 61