-aflu cati moli de alcool si de fenol intra in reactie
M,CH3OH=32g/mo;
M,C6H5OH= 94g/mol
x (32+94)=2,52-----> x= 0,02mol
-alcoolul nu reactioneaza cu NaOH
1mol............1mol
C6H5OH + NaOH-----> C6H5ONa+H2O
0,02mol......0,02mol
m= nxM
m= 0,02molx (23gNa+16gO+1gH)/mol=..............................calculeaza !!!