x-(x/3+3)-{1/3•[x-(x/3+3)] +3}=123
x-(x+9/3)-{1/3•[x-(x+9/3)+3}=123
x-(x+9/3)-[1/3•(3x-9-x/3)+3]=123
x-(x+9/3)-(2x-9/9+3)=123
x-(x+9/3)-(2x-9+27/9)=123
9x-(3x+27)-2x+9-27=1107
9x-3x-27-2x+9-27=1107
4x-45=1107
4x=1152
x=288
asa as zice ca e
• inseamna inmultire