👤

rezolvati ecuatia exponentiala

[tex] 4^{x+1} = \frac{1}{ \sqrt[3]{128} } [/tex]


Răspuns :

[tex] 2^{2x+2}= 2^{- \frac{7}{3} } \\ 2x+2=- \frac{7}{3} \\ 2x=- \frac{7}{3}-2 \\ 2x=- \frac{13}{3} \\ x=- \frac{13}{6} [/tex]