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x+y-z=1999 si y=3x. Aratati ca daca z<5, atunci z =

Răspuns :

x+y-z=1999
y=3x
x+3x-z=1999
4x-z=1999
z<5
Daca z=4
4x-4=1999
4x=2003
x=500,75

Daca z=3
4x-3=1999
4x=2002
x=500,5

Daca z=2
4x-2=1999
4x=2001
x=500,25

Daca x=0
4x-0=1999
4x=1999
x=499,75