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aflati x,y,z in progresie aritmetica in sirul x, 10,y, 22,z

Răspuns :

y=(10+22)÷2=32÷2=16, x=(2×10-y=20-16=4, z=2×22-y=44-16=28. Avem : x=44, y=16, z=28
daca is in prog aritmetica pe aia ii afli gen:
10=(x+y)/2
apoi
y=(10+22)/2
22=(y+z)/2