a+b+c = 1 168
b = a+7
b = c:3 => c = 3×b
a |___|
b |___|+7
c |___|___|___|+21 ( 3×7)
avem 5 segmente egale +7+21 = 1 168
1 168 -( 21+7) = 1 168-28 = 1 140
1 140 : 5 = 228 ( un segment)
a = 228
b = 228+7 = 235
c = 3×228+21 = 684+21 = 705
Verificare:
228+235+705 = 1 168
a = 228
b = 235
c = 705