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Descompuneti in factori -3x2+2x+1=-3(x-x1)(x-x2)

Răspuns :

-3x²+2x+1=0
Δ=4+12=16
x1=(-2-4)/(-6)=1
x2=(-2+4)/(-6)=2/(-6)=-1/3
-3x²+2x+1=-3(x-1)(x+1/3)